Calculation with Significant Figures One common bathtub is 13.44 dm long, 5.920 dm wide, and 2.54 dm deep. Assume that the tub is rectangular and calculate its approximate volume in liters.

Solution V=l×w×d=13.44 dm×5.920 dm×2.54 dm=202.09459…dm3(value from calculator)=202 dm3, or 202 L(answer rounded to three significant figures)V=l×w×d=13.44 dm×5.920 dm×2.54 dm=202.09459…dm3(value from calculator)=202 dm3, or 202 L(answer rounded to three significant figures)

Check Your Learning What is the density of a liquid with a mass of 31.1415 g and a volume of 30.13 cm^{3}? Answer:

1.034 g/mL